Answer:
The probability of the number of starfish dropping below 3 is 0.0463.
Step-by-step explanation:
Let X represent the number of starfish in the tide pool.
X follows a Poisson distribution with mean 6.4.
The formula for Poisson distribution is as follows.
![P(X=x) = e^{-6.4} * [6.4^{x} / x!] when x = 0, 1, ...](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20e%5E%7B-6.4%7D%20%2A%20%5B6.4%5E%7Bx%7D%20%2F%20x%21%5D%20when%20x%20%3D%200%2C%201%2C%20...)
otherwise
We need to find the probability that the number of starfish in the tide pool drops below 3.
Therefore, the required probability is:
P(X < 3) = P(X = 0) + P(X = 1) + P(X=2)
P(X < 3) = 0.00166 + 0.01063 + 0.03403
P (X < 3) = 0.0463
Answer:
6224 Brand X residents and 9335 Brand Y residents
Step-by-step explanation:
Total number of residents in the survey=15559
Residents that prefer Brand X=40%
Residents that prefer Brand Y=60%
<u>Population sample?</u>
Residents that prefer Brand X= 40/100 ×15559 =6223.6⇒6224 residents
Residents that prefer Brand Y= 60/100 × 15559 =9335.4⇒⇒9335 residents
The answer is irregular because speak is the base word and spoke is its past word
Answer: First Option : Sₙ= n/2(a₁ + aₙ)
Step-by-step explanation:
The nth partial sum of an arithmetic sequence or the sum of the first n terms of the arithmetic series can be defined as the sum of a finite number of term in an arithmetic sequence.
It is calculated using the formula:
Sₙ= n/2(a₁ + aₙ)
Where :
a₁ = First term
aₙ = last term
n = number of terms
Answer:
A = 5
B = 9
Step-by-step explanation:
This was very simple!
Nancy needs at least 15 boxes of travoprost but she only has 10. To find out how many she needs, we subtract 15 from 10 to get 5 boxes
Nancy also needs at least 12 boxes of latanoprost but she only has 3. To find out how many she needs, we subtract 12 from 3 to get 9 boxes
Therefore A = 5 boxes; B = 9 boxes
<em>PLEASE DO</em><em> </em><em>MARK ME</em><em> </em><em>AS BRAINLIEST</em><em> </em><em>IF MY</em><em> </em><em>ANSWER IS</em><em> </em><em>HELPFUL</em><em> </em><em>;</em><em>)</em>
