Matsuki is very very bored...<br><br> 34 + 35 x (60/2)

I’m not sure how to slove this problem it’s a equilateral triangle and I’m trying to find out what the side is equal to.

Lerok [7]

Answer:

AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

Step-by-step explanation:

Because it is a equilateral triangle, it means all sides have the same length.

AB = AC

5/4 y - 1 = 7/3 y - 2

5/4 y - 7/3 y = -2 +1

-13/12 y = -1

y = 12/13

input y to the equation.

AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

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6 0

2 years ago

In a given year, the average annual salary of a NFL football player was $189,000 with a standard deviation of $20,500. If a samp

nika2105 [10]

Answer:

15.15% probability that the sample mean will be $192,000 or more.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 189000, \sigma = 20500, n = 50, s = \frac{20500}{\sqrt{50}} = 2899.14$

The probability that the sample mean will be $192,000 or more is

This is 1 subtracted by the pvalue of z when X = 192000. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{192000 - 189000}{2899.14}$

$Z = 1.03$

$Z = 1.03$ has a pvalue of 0.8485.

1-0.8485 = 0.1515

15.15% probability that the sample mean will be $192,000 or more.

7 0

2 years ago

A rope forms 2 30 feet lines.

Nikitich [7]

................ what else?

3 0

3 years ago

A brother and a sister are in the same math class. There are 8 boys and 10 girls in the class. One boy and one girl are randomly

lara31 [8.8K]

Well, there are 8 boys and the brother is one of them so 1 is 12.5% of 8 and out of 10 girls, there 1 is the sister and 1 out of 10 is 10%. Now we multiply the percentages to get the answer 1/80

8 0

3 years ago

Read 2 more answers

Let x be the amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train. Suppose that the d

babymother [125]

Answer:

a) P (x is less than 11 minutes) = 0.55

P (x is more than 14 minutes) = 0.3

b) P (x is between 8 and 13 minutes) = 0.25

c) P(x < c) =0.8 is 0.05 x c = 0.8

Step-by-step explanation:

a) P (x is less than 11 minutes) = 11 x 0.05

= 0.55

P (x is more than 14 minutes) = 0.05 x (20 - 14)

= 0.05 x 6

= 0.3

b) P (x is between 8 and 13 minutes) = 0.05 x (13 -8)

= 0.05 x 5

= 0.25

c) P(x < c) =0.8

The area between 0 and c is 0.8

Hence,

0.05 x c = 0.8

3 0

2 years ago

Read 2 more answers

Matsuki is very very bored... 34 + 35 x (60/2) - (40/2) = ?