Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
Answer:
19,27 cm^2
Step-by-step explanation:
area of triangle = (6 x 3)/ 2 = 9 cm^2
circle area : 3^2 x 3,14 = 28,27 cm^2
area of shaped region = 28,27 - 9 = 19,27 cm^2
X + y = 24....multiply by -3
3x + 5y = 100
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-3x - 3y = - 72 (result of multiplying by -3)
3x + 5y = 100
--------------add
2y = 28
y = 28/2
y = 14
x + y = 24
x + 14 = 24
x = 24 - 14
x = 10
solution is (10,14)...and x represents 3 point q's and y represents 5 point q's......so this tells me there are 10 three point q's and 14 five point q's.
Answer:
24
Step-by-step explanation:
Answer:
x:-2
y:2
Step-by-step explanation:
