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jonny [76]
3 years ago
12

Please help me! So confused on the difference between the two and how to work them out!​

Mathematics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

A. 45

B. 684

The Least Common Multiple ( LCM ) is also referred to as the Lowest Common Multiple ( LCM ) and Least Common Denominator ( LCD) . For two integers a and b, denoted LCM(a,b), the LCM is the smallest integer that is evenly divisible by both a and b.

LCM= A. 45

Ymorist [56]3 years ago
3 0

Answer:

9 and 15

Step-by-step explanation:

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3 years ago
Math quest after a winter storm, the depth of the snow on cherry street was 10 \text{ cm}10 cm10, space, c, m. but then, the sno
Zanzabum

Answer:

9 cm.

Step-by-step explanation:

Let x be the number of hours.

We have been given that after a winter storm, the depth of the snow on cherry street was 10 cm. Then, the snow started melting at a rate of \frac{1}{3}, so the snow melted in x hours will be \frac{1}{3}x.

Since initially there was 10 cm of snow, so the depth of snow after x hours will be:

10-\frac{1}{3}x

To find the depth of snow after 3 hours we will substitute x=3 in our expression.

10-\frac{1}{3}\times 3

10-1

9

Therefore, the depth of the snow on cherry street after 3 hours will be 9 cm.

3 0
3 years ago
Read 2 more answers
A.) find the test statistic
Arada [10]

Regarding the hypothesis tested in this problem, it is found that:

a) The test statistic is: t = 0.49.

b) The p-value is: 0.6297..

c) The null hypothesis is not rejected, as the p-value is greater than the significance level.

d) It appears that the students are legitimately good at estimating one minute, as the sample does not give enough evidence to reject the null hypothesis.

<h3>What is the test statistic?</h3>

The test statistic of the t-distribution is given by the equation presented as follows:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

In which the variables of the equation are given as follows:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the hypotheses.
  • s is the standard deviation of the sample.
  • n is the sample size.

The value tested at the hypothesis is:

\mu = 60

From the sample, using a calculator, the other parameters are given as follows:

\overline{x} = 62.47, s = 19.2, n = 15

Hence the test statistic is obtained as follows:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{62.47 - 60}{\frac{19.2}{\sqrt{15}}}

t = 0.49.

<h3>What are the p-value and the conclusion?</h3>

The p-value is obtained using a t-distribution calculator, with a two-tailed test, as we are testing if the mean is different a value, in this case 60, with:

  • 15 - 1 = 14 df, as the number of degrees of freedom is one less than the sample size.
  • t = 0.49, as obtained above.

Hence the p-value is of 0.6297.

Since the p-value is greater than the significance level of 0.01, the null hypothesis is not rejected, attesting to the ability of the students to estimate one minute.

More can be learned about the test of an hypothesis at brainly.com/question/13873630

#SPJ1

5 0
1 year ago
(5/10)^4 in exponential form
Whitepunk [10]

Answer:

6.25 \times  {10}^{ - 2}

Step-by-step explanation:

{ \bigg( \frac{5}{10} \bigg) }^{4}  \\  \\  =  {(0.5)}^{4}  \\  \\  = 0.0625 \\  \\  = 6.25 \times  {10}^{ - 2}

6 0
3 years ago
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Write the ratio as a fraction in lowest terms. Be sure to make necessary conversions:
agasfer [191]

Answer:12533

Step-by-step explanation:

4 0
3 years ago
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