All categories

2 years ago

How do we Factorise 5y -6 py

Mathematics

1 answer:

____ [38]2 years ago

3 0

Answer:

See explanation.

Step-by-step explanation:

$5y-6py$

Common factor: y

$y(5-6p)$

You might be interested in

Order the following from greatest to least 1/4, 0.33, 1/8, 0

schepotkina [342]

Answer: 0.33 , 1/4 , 1/8 , 0

Step-by-step explanation:

1/4 is 0.25

1/8 is 0.125

After converting to decimal it’s all easy

4 0

2 years ago

Read 2 more answers

Michael sold his painting for $50. He sold his painting for $10 less than its original price. At what price did Michael buy the

netineya [11]

It would be 60. He sold his painting for 50 which was 10 less that the original price. So 50+10=60

7 0

2 years ago

Read 2 more answers

What is the measure of the smallest angle? 52° 61° 67° 69°

Reika [66]

52 Degrees is the smallest measure :)

4 0

2 years ago

Read 2 more answers

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$