Answer: 7208 remainder 5
Step-by-step explanation:
Answer:
Q1. x= 18, y=59
Q2. m∠J= 56°
Step-by-step explanation:
Q1. (3x +5)°= y° (base ∠s of isos. △)
y= 3x +5 -----(1)
(3x +5)° +y° +(4x -10)°= 180° (∠ sum of △)
3x +5 +y +4x -10= 180
7x +y -5= 180
7x +y= 180 +5
7x +y= 185 -----(2)
Substitute (1) into (2):
7x +3x +5= 185
10x= 185 -5
10x= 180
x= 180 ÷10
x= 18
Substitute x= 18 into (1):
y= 3(18) +5
y= 59
Q2. (5x -13)°= (3x +17)° (base ∠s of isos. △)
5x -13= 3x +17
5x -3x= 17 +13
2x= 30
x= 30 ÷2
x= 15
∠LKJ
= 3(15) +17
= 62°
∠KLJ= 62° (base ∠s of isos. △)
m∠J
= 180° -62° -62° (∠ sum of △JKL)
= 56°
You first need to isolate the y
4x+9y=-108
9y=-4x-108 (subtract 4x from both sides)
y=-4/9x-12 (divide both sides by 9)
Then, by using the y=mx+b form, we can tell that the y-intercept is -12 so A
Hope this helps
Answer:
sin70°
Step-by-step explanation:
Given sin110° where 110° is an obtuse angle in the second quadrant.
The related acute angle in the first quadrant is 180° - 110° = 70°
Thus
sin110° = sin70°
