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sertanlavr [38]
3 years ago
12

Simplify this fraction: 2160/10

Mathematics
2 answers:
murzikaleks [220]3 years ago
7 0

Answer:

216

Step-by-step explanation:

2160/10 simplified is 216

sergejj [24]3 years ago
3 0

Answer:

216

Step-by-step explanation:

2160 divided by 10 is 216.

hope this helps ;)

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Rose has 5 times as many stickers as John. They have 300 stickers in all. How many more stickers does Rose have than John? Show
kirill115 [55]

5x+x=300

6x=300

x=50

5(50)=250 (Rose)

x=50(John)

Rose has 250 stickers and John has 50, therefore Rose has 200 more stickers than John.

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3 years ago
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HELP PLEASE 13 POINTS
dimulka [17.4K]

Answer:

164

Step-by-step explanation:

The formula is *4

41*4=164

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2 years ago
Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g
AysviL [449]

Answer:

The quantity of salt at time t is m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} }), where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}

Where:

c - The salt concentration in the tank, as well at the exit of the tank, measured in \frac{pd}{gal}.

\frac{dc}{dt} - Concentration rate of change in the tank, measured in \frac{pd}{min}.

V - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

V \cdot \frac{dc}{dt} + 6\cdot c = 3

60\cdot \frac{dc}{dt}  + 6\cdot c = 3

\frac{dc}{dt} + \frac{1}{10}\cdot c = 3

This equation is solved as follows:

e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }

\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }

e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt

e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C

c = 30 + C\cdot e^{-\frac{t}{10} }

The initial concentration in the tank is:

c_{o} = \frac{10\,pd}{60\,gal}

c_{o} = 0.167\,\frac{pd}{gal}

Now, the integration constant is:

0.167 = 30 + C

C = -29.833

The solution of the differential equation is:

c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }

Now, the quantity of salt at time t is:

m_{salt} = V_{tank}\cdot c(t)

m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })

Where t is measured in minutes.

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3 years ago
Raphael works 12 hours each week. He earns £4 per hour. Tom saves 1/3 of earnings each week. How many weeks does it take Tom to
olga_2 [115]

Raphael works 12 hours each week. He earns £4 per hour. Tom saves 1/3 of earnings each week. How many weeks does it take Tom to save £80?

5 weeks

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Which list orders -3,2,5, -1 From least to greatest
seropon [69]
The answer is: -3,-1,2,5
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3 years ago
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