hopefully someone helps u with this tho sorry
Answer:
Length of side of rhombus is
Step-by-step explanation:
Given Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC. We have to find the length of side of rhombus.
It is also given that AB=a and AC=b
Let side of rhombus is x.
In ΔCEF and ΔCBA
∠CEF=∠CBA (∵Corresponding angles)
∠CFE=∠CAB (∵Corresponding angles)
By AA similarity rule, ΔCEF~ΔCBA
∴ their sides are in proportion

⇒ 
⇒ 
⇒ 
⇒ 
Hence, length of side of rhombus is
<span> 7x+2y=5;13x+14y=-1 </span>Solution :<span><span> {x,y} = {1,-1}</span>
</span>System of Linear Equations entered :<span><span> [1] 7x + 2y = 5
</span><span> [2] 13x + 14y = -1
</span></span>Graphic Representation of the Equations :<span> 2y + 7x = 5 14y + 13x = -1
</span>Solve by Substitution :
// Solve equation [2] for the variable y
<span> [2] 14y = -13x - 1
[2] y = -13x/14 - 1/14</span>
// Plug this in for variable y in equation [1]
<span><span> [1] 7x + 2•(-13x/14-1/14) = 5
</span><span> [1] 36x/7 = 36/7
</span><span> [1] 36x = 36
</span></span>
// Solve equation [1] for the variable x
<span><span> [1] 36x = 36</span>
<span> [1] x = 1</span> </span>
// By now we know this much :
<span><span> x = 1</span>
<span> y = -13x/14-1/14</span></span>
<span>// Use the x value to solve for y
</span>
<span> y = -(13/14)(1)-1/14 = -1 </span>Solution :<span><span> {x,y} = {1,-1}</span>
<span>
Processing ends successfully</span></span>
Dividing fractions is the same as multiplying by its reciprocal so you can change the equation to this

And you can simplify by eliminating the fours and multiplying straight across

You can pull out - 7 from the top and 2 from the bottom so you have this

And then you can cancel out to (2-x) to get an answer of
Answer:
y - 5 = -3(x - 12)
Step-by-step explanation:
Point slope form is: y - y1 = m(x - x1), where (x1, y1) is a point on the line, and m is the slope of the line.
Plug in the point and the slope:
y - y1 = m(x - x1)
y - 5 = -3(x - 12)
So, y - 5 = -3(x - 12) is the equation in point slope form of the line.