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ASHA 777 [7]
3 years ago
9

Question 1 (1 point)

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0

Answer:

B. false

Step-by-step explanation:

Square units

I hope that is useful for you :)

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Which values of PP and QQ result in an equation with no solutions? -60x+32=Qx+P−60x+32=Qx+P Choose all answers that apply: Choos
Inga [223]
<h3>Answer:</h3>

  A and C

<h3>Step-by-step explanation:</h3>

Given:

  -60x+32 = Qx+P

Find:

Which values of P and Q result in an equation with no solutions? Choose all answers that apply:

(Choice A) A Q=-60 P=60

(Choice B) B Q=32 P=60

(Choice C) C Q=-60 P=−32

(Choice D) D Q=32 P=−60

Solution:

The equation will have no solution if it reduces to ...

  0 = (non-zero constant)

If we add 60x-32 to both sides, we get

  0 = 60x +Qx + P-32

  0 = (Q+60)x +(P-32)

The x-term must be zero, so Q+60 = 0, or Q = -60.

The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.

The appropriate answer choices are those with Q=-60 and P≠32, A and C.

8 0
3 years ago
Given the function below, find /(-7)<br> (X) = -2x-1
Lostsunrise [7]

For this case we have a function of the formy = f (x)where:

f (x) = - 2x-1

We must find the value of the function whenx = -7. So:

f (-7) = - 2 (-7) -1

By definition we have to:

- * - = +\\f (-7) = 14-1 = 13

Thus, the value of the function is y = 13

Answer:

y = f (-7) = 13

7 0
3 years ago
(1 point) solve the separable differential equation y′(x)=2y(x)+18−−−−−−−−−√, y′(x)=2y(x)+18, and find the particular solution s
luda_lava [24]
We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9)) 

Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>

Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>

<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>

Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2

<span>sqrt(y+9) = (2x + 2) / 2sqrt(2) 
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>

y = ((2x+2)^2) / 8 - 9
7 0
3 years ago
Write an equation for the following situation: 15 less than a number is equal to 12
weeeeeb [17]
Break it down
"15 less than " means -15
"a number" means unknown or placeholder means x
"is equal to" means '='
'12' means 12
-15+x=12
add 15
x=27
3 0
3 years ago
In your lab, a substance's temperature has been observed to follow the function T(x) = (x − 4)3 + 6. The turning point of the gr
Montano1993 [528]

Yo sup??

To find the turning point we have to differentiate the given function.

T(x)=(x-4)3+6

T'(x)=3

Therefore the turning point is at 3

Hope this helps.

8 0
3 years ago
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