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Sergio039 [100]
4 years ago
9

Factor completely and then place the factors in the proper location on the grid. 4n 2 + 28n + 49

Mathematics
2 answers:
kumpel [21]4 years ago
7 0
The equation is a perfect square binomial (2n+7)^2.
Tema [17]4 years ago
5 0

Answer:

The given  quadratic equation 4n^2+28n+49 factored as (2n+7)^2=(2n+7)(2n+7)

Step-by-step explanation:

   Given quadratic equation 4n^2+28n+49  

We have to factorize the given quadratic equation and make the grid of factors.

Consider the given quadratic equation 4n^2+28n+49  

Using algebraic identity,

(a+b)^2=a^2+2ab+b^2

On comparing, we get,

a^2=4n^2\\\\ \Rightarrow a=2n

also, b^2=49\\\\\Rightarrow b=7

Thus, the given  quadratic equation 4n^2+28n+49 factored as (2n+7)^2=(2n+7)(2n+7)

The grid is shown in attachment below.

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  • The distribution is skewed left.
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brainly.com/question/304810

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