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Bogdan [553]
3 years ago
5

The cost of a plane ticket increases by 12%. After the increase, the ticket costs $616. What was the cost before the increase? E

xplain your answer using complete sentences.
Mathematics
1 answer:
Zina [86]3 years ago
7 0

The cost before increase was $550.

Step-by-step explanation:

Given,

Increased price of plane ticket = $616

Increase percent = 12%

Let,

x be the original price of ticket.

Now,

The original price is 100% and 12% is increased, therefore;

New price = (100+12)% = 112%

Thus;

$616 is 112% of x.

112% of x = 616

\frac{112}{100}x=616\\1.12x=616

Dividing both sides by 1.12

\frac{1.12x}{1.12}=\frac{616}{1.12}\\x=550

The cost before increase was $550.

Keywords: division, percentage

Learn more about division at:

  • brainly.com/question/10570041
  • brainly.com/question/10610299

#LearnwithBrainly

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to solve  for the dimensions (x+7)(x+2)=66,

we can first use the foiling method to simplify the left side.

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now, subtract 66 from both sides.

x^2 + 9x - 52 = 0

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Miguel borrowed $825 for a new couch. He will make 9 monthly payments of $95 to repay the loan. How much will he pay in interest
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Answer:

$30 is paid in interest.

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Answer:

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\sigma^2 =32.4

\sigma = 5 .7

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Step-by-step explanation:

Given

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Solving (a): The range

This is calculated as:

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So:

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Solving (b): The variance

First, we calculate the mean

\bar x = \frac{1}{n} \sum x

\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)

\bar x = \frac{1}{6} *810

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The variance is calculated as:

\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2

So, we have:

\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]

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\sigma = \sqrt {\sigma^2 }

\sigma = \sqrt {32.4}

\sigma = 5 .7 --- approximately

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