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2 years ago

Evaluate 75% of 3/4.........................

Mathematics

1 answer:

julia-pushkina [17]2 years ago

6 0

#The 75% of 3/4?

#Just times it.

75/100 × 3/4 = 225/400 =9/16

#so, the 75% of 3/4 is 9/16

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Simplify the rational expression. State any restrictions on the variable.

ExtremeBDS [4]

we are given

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}$

Firstly, we will factor numerators and denominators

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-6)(n^2-4)}{(n^2-3)(n^2-6)}$

we can see that

n^2 -6 is factor on both numerator and denominator

so, it will get cancelled

and n^2 -6 can not be equal to 0

so, one of restriction is

$n^2-6\neq 0$

$n\neq -+ \sqrt{6}$

we can simplify it

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-4)}{(n^2-3)}$

we know that denominator can not be zero

$n^2-3\neq 0$

$n\neq -+ \sqrt{3}$

so, option-B.......Answer

3 0

2 years ago

In how many ways can we seat 6 people around a round table if Fred and Gwen insist on sitting opposite each other? (Two seatings

vivado [14]

I think 8 differnt ways

8 0

2 years ago

Solve for m m m Please help!!!

jarptica [38.1K]

Answer:

m∠ TRS = 60° , m∠ SRW = 120°

Step-by-step explanation:

First, find x

∠TRS = ∠VRW (vertically opposite angles are equal)

x + 40° = 3x

x - 3x = -40

-2x = -40

x = -40/-2

x = 20

m∠ TRS = 60° [x + 40 = 20+40 = 60]

m∠ SRW + m∠ TRS = 180° (linear pair)

m∠ SRW + 60° = 180°

m∠ SRW = 180° - 60°

m∠ SRW = 120°

hope this helps you

6 0

2 years ago

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago

Mieko said that the difference between the longest rose and the shortest rose is 1 inch. Is she correct?

erastova [34]

Answer:

Mieko is correct

Step-by-step explanation:

Given

See attachment for complete question

Required

The length difference

Lengths with dot(s) means, there is at least 1 rose flower of that length.

So, from the attachment, we have:

$Longest = 14.0$

$Shortest = 13.0$

The difference (d) is:

$d = Longest - Shortest$

This gives:

$d = 14.0 - 13.0$

$d = 1\ in$

Hence, Mieko is correct

3 0

1 year ago