Write an equation in slope intercept form m=2,(3,1)
1 answer:
<h2>Answer:</h2>
First, we must find the y-intercept of the line given the slope and a point on the line and pluging it into <em><u>slope-intercept form*</u></em>.
Now that we have the y-intercept, we can create the equation of this line.
*Slope-intercept form: <em>y = mx + b </em>← y-intercept
↑
slope
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We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
Answer:
y=7x-188
Step-by-step explanation:
We know that this line must have a slope of 7, because this line is parallel to y=7x+13
We must use the point slope formula: y-= m(x-
)
Next, we will plug in the point (28,8) for and
, and 7 in for m
y-8=7(x-28)
Solve the equation, first by distributing the 7
y-8=7x-196
Add the 8 over
y=7x-188