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uysha [10]
2 years ago
10

Write an equation in slope intercept form m=2,(3,1)​

Mathematics
1 answer:
Art [367]2 years ago
8 0
<h2>Answer:</h2>

First, we must find the y-intercept of the line given the slope and a point on the line and pluging it into <em><u>slope-intercept form*</u></em>.

1 = 2(3) + b\\\\1 = 6 + b\\\\-5 = b

Now that we have the y-intercept, we can create the equation of this line.

y = 2x - 5

*Slope-intercept form: <em>y = mx + b </em>← y-intercept

                                           ↑

                                         slope

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Can someone please teach me how to add, subtract, multiply and divide negative numbers?
dedylja [7]
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if there is more positive ur answer will be a positive. so number 2 is 13.
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3 0
3 years ago
Read 2 more answers
Last one, ​please :)
KengaRu [80]

Answer:

m∠X = 29°

m∠V = 61°

m∠W == 90°⇒given

Step-by-step explanation:

∵ ΔXWV is right angle at W

∴ m∠W = 90°

∴ m∠X + m∠V = 180° - 90° = 90°

∵ m∠X = 2x + 5 and m∠V = 4x +13

∴ 2x + 5 +4x + 13 = 90

∴ 6x + 18 = 90

∴ 6x = 90 - 18 =72

∴ x = 72/6 = 12

∴ m∠X = 2(12) + 5 = 29°

∴ m∠V = 4(12) + 13 = 61°

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3 years ago
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Leya [2.2K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

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