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3 years ago

The following statements is are true regarding the figure above

Mathematics

2 answers:

Andreyy893 years ago

7 0

Answer:

a and b

Step-by-step explanation:

it is a point and a point is a zero demensional object.

icang [17]3 years ago

3 0

The answer is a and b

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What times what gives you 15 but when added gives you 8?

UNO [17]

Answer: 5 x 3 = 15 because 5 + 3 = 8

Step-by-step explanation:

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3 years ago

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Please help me asappp (will give brainiest!)

ryzh [129]

Answer:

TanФ=-1.793

Step-by-step explanation:

$Sin^{2} (A) + Cos^{2} (A) = 1$

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3 years ago

Salma is training for a marathon. This week she wants to run a total of 60 miles. She ran 8.55 miles on each of the first 3 days

MArishka [77]

Answer:

51.45 miles

Step-by-step explanation:

7 days = 60 miles

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60 - 8.55 = 51.45 miles

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3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

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3 years ago

if you draw one card from a standard deck, what is the probability of drawing a diamond or a red card?

Aleks [24]

Answer:

3/4 probability

probability to draw a red card = 11/26

probability to draw a diamond =1/4

probability of drawing one or other card = 35/52

# actually i am not sure

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3 years ago

The following statements is are true regarding the figure above​

The following statements is are true regarding the figure above