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Evgen [1.6K]
3 years ago
6

Please help and thank you!!!

Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0

Answer:

12) 8700

13) 42

14) 70000

15) 5000000000

16) 2210

17) 34100

18) 1650

19) 149

20) 290000

Jlenok [28]3 years ago
6 0

Answer:

Step-by-step explanation:

12: 8,700

13: 42

14: 70,000

15: 5,000,000,000

16: 2,210

17: 34,100

18: 1,650

19: 149

20: 290,000

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Salsk061 [2.6K]
Hi there!

First of all we need to remember the number 6.32.

It could be any of the following:
6.323 OR 6.324

We are rounding UPPP! If you were to round down it would be 6.32 or less.

Hope this helped!
5 0
3 years ago
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A rectangle has a length of 11 meters less than 10 times its width. If the area of the rectangle is 9888 square meters, find the
kobusy [5.1K]

Step-by-step explanation:

The Length ,

L

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284

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t

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Explanation:

Given:

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A

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L

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W

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E

q

u

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t

i

o

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substitute to

e

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u

a

t

i

o

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A

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(

L

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(

W

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e

q

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a

t

i

o

n

2

A

=

(

10

W

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(

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8804

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(

10

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(

W

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factor

8804

=

2

(

5

W

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13

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(

W

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divide both sides by 2

4402

=

(

5

W

−

13

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(

W

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4402

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5

W

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transposing 4402 to the right side of the equation

0

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5

W

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13

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W

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−

(

−

13

)

+

√

(

−

13

)

2

−

4

(

5

)

(

−

4402

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2

(

5

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W

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[

13

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169

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88040

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10

W

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+

(

√

88209

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10

W

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13

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297

10

W

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310

10

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31

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W

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26

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10

(

31

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284

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answer

W

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−

(

−

13

)

−

√

−

(

−

13

2

)

−

4

(

5

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(

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2

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8 0
3 years ago
A large rectangular movie screen in an IMAX theater has an area of 8,364 square feet. Find the dimensions of the screen if it is
jeyben [28]

Answer:

The dimensions of the screen are

Length:102 feet

Width: 82 feet

Step-by-step explanation:

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L is the length

W is the width

we have

A=8,364\ ft^2

so

8,364=LW ----> equation A

The screen is 20 feet longer than it is wide.

so

L=W+20 ---> equation B

substitute equation B in equation A

8,364=(W+20)W

solve for W

8,364=W^2+20W\\W^2+20W-8,364=0

solve the quadratic equation by graphing

the solution is W=82 ft

see the attached figure

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L=82+20=102\ ft

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Width: 82 feet

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HELP CONGRUENT ANGLES
Gemiola [76]
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