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Evgen [1.6K]
3 years ago
6

Please help and thank you!!!

Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0

Answer:

12) 8700

13) 42

14) 70000

15) 5000000000

16) 2210

17) 34100

18) 1650

19) 149

20) 290000

Jlenok [28]3 years ago
6 0

Answer:

Step-by-step explanation:

12: 8,700

13: 42

14: 70,000

15: 5,000,000,000

16: 2,210

17: 34,100

18: 1,650

19: 149

20: 290,000

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For which values of x is the function
max2010maxim [7]

Answer:

x = - 5, x = - 11

Step-by-step explanation:

Given

y = \frac{x+4}{(x+5)(x+11)}

The denominator cannot be zero as this would make y undefined.

Equating the denominator to zero and solving gives the values that x cannot be, that is

(x + 5)(x + 11) = 0

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x + 11 = 0 ⇒ x = - 11

Thus

x = - 11 and x = - 5 are excluded values.

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3 years ago
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Answer:

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Step-by-step explanation:

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Find the least common multiple of these two expressions.<br> 10v^6y^7 and 6w^4v^5y^3
egoroff_w [7]

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LCM: 2v⁴y³ * (5 * v * yyyy) * (3 * wwww)

       = (2 * 5 * 3) * (v⁴ * v) * (w⁴) * (y³ * y⁴)

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4 0
3 years ago
A 63 foot long cable is anchored in the ground and
myrzilka [38]

Answer:

The height of the light pole to the nearest foot is approximately 50 feet

Step-by-step explanation:

The parameters given in the question are;

The length of the cable = 63 feet

The angle of elevation of the cable to the top of the light pole = 52°

With the assumption that the light pole is perpendicular to the ground, the figure formed by the light pole, the distance of the of the cable from the base of the light pole and the length of the cable form a right triangle

The question can be answered by using trigonometric relations for the sine of the given angle as follows;

sin ( \theta) = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}

The opposite leg length of the formed right triangle = The height of the light pole

The hypotenuse length = The length of the cable = 63 feet

The angle, θ = The angle of elevation = 52°

Plugging in the values, gives;

sin (52 ^ {\circ}) = \dfrac{The \ height \ of \ the \ light \ pole }{63 \ feet}

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The height of the light pole to the nearest foot ≈ 50 feet.

8 0
3 years ago
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