Let D be dogs and C be cats
<em>dogs, d, is initially five less than twice the number of cats, c</em>
D + 5 = 2C
<em>If she decides to add three more of each, the ratio of cats to dogs will be</em>
D + 8 = 2C + 3
<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>
Simply plug in the numbers
20 + 5 = 2(15)
This is clearly not true: 25 does not equal 30
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Answer:
There are 76 students:
g + b = 76
girls is 13 more than twice the boys:
g = 2b + 13
replace g with 2b + 13 in 1st equation
2b+13+b = 76
3b + 13 = 76
3b = 63
b = 21 boys
g = 76-21 = 55 girls
Step-by-step explanation:
<em>Subtract</em> 2/3x on both sides.
Combine 5/3x and -2/3x to get x.
Subtract 4 from both sides. <em>Any value</em> subtracted from zero results in its negative value.
R = # of Gladiolus Mrs. Rouse has
L = # of gladiolus Mrs. Leal has
R = 3L
R+L = 128
Solution for number of Gladiolus each has
3L + L = 128
4L = 128
L = 32
R = 3(32) = 96
