Question

HELP HELP I don’t know how to do thissssss

Answer 1

Answer:

see below

Step-by-step explanation:

$p(x)=x^3-3x-1$  and  $q(x)=x-1$

$p(x)+q(x)=(x^3-3x-1)+(x-1)=x^3 -2x-2$

$p(x)-q(x)=(x^3-3x-1)-(x-1)=x^3 -3x-1-x+1=x^3-4x$

$p(x) \times q(x)=(x^3-3x-1)(x-1)=x^4-x^3-3x^2+2x+1$

$\frac{p(x)}{q(x)} =\frac{x^2-3x-1}{x-1} =x^2+x-2-\frac{3}{x-1}$  

Answer 2

Step-by-step explanation:

p(x) + q(x) = x^3 - 3x - 1 + x - 1= x^3 - 2x - 2

p(x) - q(x) = x^3 - 3x - 1 - x + 1 = x^3 - 4x

p(x) x q(x) = (x^3 - 3x - 1) (x-1) = x^4- x^3 - 3x^2 +3x -x +1 = x^4 - x^3 -3x^2 + 2x +1

p(x) : q(x) = x^3 - 3x - 1/ x - 1= x( x^2 - 3 - 1) / x - 1