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2 years ago

HELP HELP I don’t know how to do thissssss

Mathematics

2 answers:

Sophie [7]2 years ago

8 0

Answer:

see below

Step-by-step explanation:

$p(x)=x^3-3x-1$ and $q(x)=x-1$

$p(x)+q(x)=(x^3-3x-1)+(x-1)=x^3 -2x-2$

$p(x)-q(x)=(x^3-3x-1)-(x-1)=x^3 -3x-1-x+1=x^3-4x$

$p(x) \times q(x)=(x^3-3x-1)(x-1)=x^4-x^3-3x^2+2x+1$

$\frac{p(x)}{q(x)} =\frac{x^2-3x-1}{x-1} =x^2+x-2-\frac{3}{x-1}$

Mila [183]2 years ago

5 0

Step-by-step explanation:

p(x) + q(x) = x^3 - 3x - 1 + x - 1= x^3 - 2x - 2

p(x) - q(x) = x^3 - 3x - 1 - x + 1 = x^3 - 4x

p(x) x q(x) = (x^3 - 3x - 1) (x-1) = x^4- x^3 - 3x^2 +3x -x +1 = x^4 - x^3 -3x^2 + 2x +1

p(x) : q(x) = x^3 - 3x - 1/ x - 1= x( x^2 - 3 - 1) / x - 1

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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were born

strojnjashka [21]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 335, \pi = \frac{268}{335} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563$

For the percentage:

Multiplying the proportions by 100.

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0

3 years ago

What is the coordinate of the midpoint of segment AC

Aloiza [94]

Answer:

-5.5

Step-by-step explanation:

$\frac{-7+-4}{2}\\\\\frac{-11}{2}\\\\-5.5$