Answer:
false
Explanation:
Answer:
Explanation:
Given the data:
X ___ : 0____ 1 ___ 2 ____ 3 ____ 4
P(X)__: 0.35_0.3___, b ___0.05_ 0.05
Σp(x) = 1
Hence,
0.35 + 0.3 + b + 0.05 + 0.05 = 1
0.75 + b = 1
b = 1 - 0.75
b = 0.25
The mean :
E(x) = Σ(X * p(x))
E(x) = (0*0.35)+(1*0.3)+(2*0.25)+(3*0.05)+(4*0.05)
E(x) = 0 + 0.3 + 0.5 + 0.15 + 0.2 = 1.15
Standard deviation = sqrt(Var(x))
Var(x) = Σx²p(x) - E(x)
Σx²p(x) = (0^2 * 0.35)+(1^2 * 0.3)+(2^2 * 0.25)+(3^2 * 0.05)+(4^2 * 0.05)
= 2.55 - 1.15
= 1.4
Sqrt(1.4) = 1.183
nothing........................................
