Question

rac{12x}{2x-3x-10} - \frac{x}{(x-5)}" alt="\frac{12x}{2x-3x-10} - \frac{x}{(x-5)}" align="absmiddle" class="latex-formula">


Help me :)

Answer 1

Answer:

Step-by-step explanation:

$\frac{12x}{2x-3x-10}-\frac{x}{x-5}=\frac{12x}{-x-10}-\frac{x}{x-5}\\\\=\frac{12x}{-(x+10)}-\frac{x}{x-5}\\\\=\frac{-12x}{x+10}-\frac{x}{x-5}\\\\=\frac{-12x*(x-5)}{(x+10)*(x-5)}-\frac{x*(x+10)}{(x-5(x+10)}\\\\=\frac{-12x*x-5*(-12x)}{(x+10)(x-5)}-\frac{x*x+x*10}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x}{(x+10)(x-5)}-\frac{x^{2}+10x}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x-(x^{2}+10x)}{(x+10)(x-5)}\\\\=\frac{-12x^{2} + 60x - x^{2}-10x}{x^{2}+5x-50}\\\\=\frac{-13x^{2}+50x}{x^{2}+5x-50}$

Answer 2

x = 5

12x = 60
————-
2x - 3x - like terms

2(5) + -3(5)

|

10 + -15 = -5

-5 + 10 (from the espression) = 5



60. 5
——— = 12. ——— = 1
5 5

So 12 - 1 = 11


11 is the answer