Answer:if there are 7 HS students for every 2 MS students and there are 18 MS students...
18/2 = 9
9(7) = 63
So, there are 18 + 63 = 81 total students.
Since we had 9 parts last year also (1:8), 81/9 = 9 students are in each part. 8 students in each part are HS and one is MS.
8(9) = 72 HS students last year.
72 - 63 = 9 fewer HS students than last year.
Hope this helps!
Answer:
A. Shift down 2 units.
B. Vertically stretch by a factor of 4.
Step-by-step explanation:
Given the function
f(x)=x
If we stretch y vertically by a factor of m, we have: y=m·f (x)
Therefore:
Vertically stretching f(x) by a factor of 4, we have: 4x.
Next, if we take down f(x) by k units we have: y= f(x)-k
Therefore: Taking down 4x by 2 units, we obtain:
g(x)=4x-2
Therefore, Options A and B applies.
Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
The "m" in y = mx + b is the <u>slope.</u>
It is the number of units a point goes up, down, left, or right each time. Making the line linear/straight.

"rise" is the the number of units you go up(+) or down(-), "run" is the number of units you go to the right
For example, if your slope is:

You are going up 1 unit, and to the right 2 units
3 or 
You are going up 3 units, and to the right 1 unit

You are going down one unit, and to the right 2 units
-3 or 
You are going down 3 units, and to the right 1 unit
Answer:
Kindly check explanation
Step-by-step explanation:
Organizations like NASA who explore space and planets often have to deal with measurement of very long distances such as the one stated above. The Major challenge with the distance written in the format expressed above is the difficulty to read, state or use in mathematical calculations as it is too explicit. A more effective method is to express this distance in standard format and more suitable long distant units such as miles.
For instance;
880,000,000,000,000,000,000,000 kilometers could be expressed as in standard form as ;
8.8 * 10^23 km