Question

Questions are in the image please help

Answer 1

For the first one use the slope formula: $m= \frac{ y_{2}- y_{1} }{ x_{2}- x_{1} }$
So for you that would look like this: $m= \frac{-4+1}{-2-7}= \frac{-3}{-9}= \frac{1}{3}$
For number 2, in order for a slope to be 0, it has to be a completely horizontal line with no steepness whatsoever.  That can ONLY happen with lines that are "y=some constant with no x".  So that answer has to be y = -5. For that last one, we have to use the slope-intercept form of a line and use the point they give us along with the slope to find the y-intercept, or the "b". That looks like this for us: $\frac{5}{6}=1(0)+b$ so b= 5/6. So our equation, fitting the slope and y intercept back in, gives us $y=x+ \frac{5}{6}$