sec((-(4 * pi)) / 3 radians) = -2
Please mark brainliest!
Answer:
B
Step-by-step explanation:
just think about it :
can it move up or down ? no, because for a specific input value still the same functional result is calculated (nothing is getting bigger or smaller).
all that is happening that way is that now, with using g(x), the original f(x) functional values happen now 2 units "later" = to the right (if you consider the x-axis a time line growing to the right). we are getting the functional value of f(x-2) at x and not at x-2 for g(x).
for example
the functional values are for x² (just some integers to make it easier) :
x = 1, 2, 3, 4, 5, ...
getting
f(1), f(2), f(3), f(4), f(5), ...
leading to
1², 2², 3² 4², 5², ...
which is
1, 4, 9, 16, 25, ...
now, let's say we start looking at x = 3
x = 3, 4, 5, 6, 7, ...
getting
g(3), g(4), g(5), g(6), g(7), ..
leading to
1², 2², 3² 4², 5², ...
which is
1, 4, 9, 16, 25, ...
so, now we are getting the functional value at e.g. x = 5 that we got originally for x = 3 (9).
therefore, under g(x) the original functional values still "happen", they just simply "happen" 2 units "later" (to the right).
in the same way
g(x) = f(x+2) moves everything 2 units to the left (now things are happening "earlier").
Answer:
2 1/2 dozen = $3.10
Step-by-step explanation:
1 dozen = 1.24
2.5 dozen = ?
2.5 × 1.24 = $3.1
Using the hypergeometric distribution, it is found that there is a 0.1333 = 13.33% probability that two of the socks will both be green if the socks are drawn without replacement.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem, we have that the values of the parameters are:
N = 10, k = 4, n = 2.
The probability that both are green is P(X = 2), hence:


0.1333 = 13.33% probability that two of the socks will both be green if the socks are drawn without replacement.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
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