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3 years ago

What is the vertex of (x) = –16x² + 64x + 80.

Mathematics

1 answer:

cricket20 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

f(x) = a(x - h)² + k - the vertex form of the equation of the parabola with vertex (h, k)

$f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}$

<u>The vertex is </u><u>(2, 124)</u>

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