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Olin [163]
3 years ago
11

What is the vertex of (x) = –16x² + 64x + 80.

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

<h3>            (2, 124)</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k      - the  vertex form of the equation of the parabola with vertex (h, k)

f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}

<u>The vertex is </u><u>(2, 124)</u>

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Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.
Bas_tet [7]

Answer:

The function touches the damping factor

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Step-by-step explanation:

Given function is f(x)=e^{-3x} sin(x) and damping factor as y=e^{-3x} and y=(-1)e^{-3x}

To find when function touches the damping factor:

For f(x)=e^{-3x} sin(x) and y=e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=e^{-3x}

sin(x)=1

x=\frac{(4n-3)\pi}{2}

For f(x)=e^{-3x} sin(x) and y=(-1)e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=(-1)e^{-3x}

sin(x)=(-1)

x=\frac{(4n-1)\pi}{2}

Therefore, The function touches the damping factor x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

To find x-intercept of f(x):

For x-intercept, y=0

f(x)=e^{-3x} sin(x)

y=e^{-3x} sin(x)

e^{-3x} sin(x)=0

Hence, e^{-3x} is always greater than zero.

Therefore,sin(x)=0

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Thus,

The x-intercept of f(x) is at x=n\pi

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3 years ago
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Burka [1]

Answer:

390 degrees

Step-by-step explanation:

The conversion factor is 180/pi

13 pi /6 * 180/pi

13/6 *180

390

5 0
3 years ago
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