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3 years ago

Can someone plz help me on this the answers are at the bottom plz

2 answers:

8 0

Formula for a cube is a=lxwxh so 3x3x3. Equals 9x3=27

3 0

Answer:

Step-by-step explanation:

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4 years ago

Yuki888 [10]

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weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$