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Anika [276]
3 years ago
6

PLEASE ANSWER ASAP

Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

Step-by-step explanation:

I'll assume these are the equations:

11x + y =  18

4x + y  = 18

-2x - 2y = 18

=======

The easiest approach to graphing, for me, is to rearrange each to y=mx+b (slope-intercept) format:

  • y = -11x+18      y-intercept of 18      (0,18)
  • y = -4x + 18     y-intercept of 18      (0,18)
  • y =   - x -9       y-intercept of -9      (0,-9)

It seems to me that all three can be graphed easily from simply reading the slope and y-intercept values.  Since these are straight lines, all we need is two points for each line, and one is standing out in plain view, the y-intercept:  (0,y-intercept).  The second point can be determined by using whatever value of x makes the calculation easy

An example:  y =  - x -9.  Plot (0,-9) for the y intercept, and then calculate one additional point (e.g., for x = - 9).  (-9,0)  Then connect a straight line between these two points and presto (metric term for magic), a graph. For the first equation, I picked 20 for x.  For x = 20, y = -29.  That was easy, and we have the second point:  (1,-10)

See the attachment for how this was done.  The first points are all for the y-intercept (0,[18 or 9]).  All of the second points were calculated in my head by using a convenient value for x.

This approach doesn't work well for non-linear equations.  There, I find it easier to set up a table of values - a spreadsheet such as Excel is my tool for the calculations.

The attachment also demonstrates the Really Easy Way to graph functions.  DESMOS, a free, and excellent, online calculator.

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Answer:

Question 1: P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}

Question 2:

A. P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

B. P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

C. P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

Step-by-step explanation:

Conditional probability is defined by

P(A|B)= \frac{P(A and B)}{P(B)}

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} }  = \frac{1}{2}

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

then

P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

so

P((YorZ) and B)= \frac{3}{16}

By definition,

P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

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The correct answer is C. 49.

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7-12 age group

23 adventure or biography

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so you just have to subtract 50 from 23, which makes it 27. The remaining belongs to the 13-18 age group.

13-18 age group

1 - detective 

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n₁ + n₂ = 12

-----------

This means that:

n₁ = 12 - n₂

And:

(12 - n₂)*$0.10 + n₂*$0.25 = $2.25

12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25

$1.20 + n₂*$0.05*(5-2) = $2.25

$1.20 + n₂*$0.05*3 = $2.25

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n₂*$0.15 = $1.05

n₂ = ($1.05)/($0.15)

n₂ = 7

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Therefore, n₁ = 5.

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Answer:

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