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zepelin [54]
3 years ago
6

192 = 3w^2 solve using square root

Mathematics
1 answer:
exis [7]3 years ago
6 0

Answer:

W=8

Step-by-step explanation:

First you divide both sides by 3 then you square root both sides getting 8

192/3=3w^2/3

64=w^2

w=8

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You ask 125 randomly chosen students their favorite sport. There are 1300 students in the school. Based on the results of the su
yan [13]

<u><em>780 students</em></u>

<u><em></em></u>

<em>Set up a proportion.</em>

<em />

<em>75 / 125 = x/1300</em>

<em />

<em>125  10.4 = 1300</em>

<em />

<em>75 * 10.4 = 780</em>

<em />

<em>x=780</em>

5 0
3 years ago
Sally's soccer team played 25
pantera1 [17]

Answer:

64%

Step-by-step explanation:

25 - 9 = 16, so 16 of the games were won by Sally's team.

16/25 = 64% of the games were won

6 0
3 years ago
V+6=92 solve for v
inysia [295]

Answer:

v = 86

Step-by-step explanation:

v + 6 = 92

v + 6 = 92

   -6      -6

v = 86

3 0
3 years ago
Read 2 more answers
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
Select all expressions that are equivalent to 12- 4x
snow_lady [41]
I think it’s just A the rest all come out with -12 after being distributed
7 0
3 years ago
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