I will create a set of arbitrary constants (x1,y1) (x2,y2)
slope = y2-y1/x2-x1
y = (y2-y1/x2-x1)x + b
y2 = (y2-y1/x2-x1)x2 + b
b = y2 - (y2-y1/x2-x1)x2
y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]
Choose any points and just
Plug the values and you have a linear function.
NOT SURE IF THAT'S WHAT THE QUESTION WANTS.
Answer:
1
Step-by-step explanation:
Well slope intercept is y2-y1 over x2-x1
So,
-6-(-9) over 9-6
3 over 3 which is 1
Your slope is 1
So, in order, you have to multiply first. 3x3=9, now you have to do 2+2=4. Since there is a "plus" in between "2+2" and "3x3" you have to add, 9+4=13.
Answer:
slope is 2/3, the y-intercept is -4
Step-by-step explanation:
y=mx+b
m is always the slope. b is always the y-intercept. please give brainliest!!
