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harina [27]
4 years ago
13

What would this be, please help me.

Mathematics
1 answer:
Sveta_85 [38]4 years ago
8 0

Answer:

I think it is 6.

Step-by-step explanation:

on a parrelelogram parrelell sides r =. this means that 6x-15=x+15

we can subtract x from both sides and get 5x-15=15. add 15 to both sides and get 5x=30. Divide both sides by 5 and get x=6.

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Tanzania [10]

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What is the range of the function?
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8 0
2 years ago
The points (-1, r) and (2, 3) lie on a line with slope -1.Find the missing coordinate r
Tomtit [17]

Answer:

r=0

Step-by-step explanation:

1) Place point (2, 3) on graph.

2) Use the slope of -1 to go left -1 and go down -1

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8 0
3 years ago
a department store holds a year-end clearance sale that includes a 19.8% discount on cosmetics. find the sale price of a bottle
Ivan

The sale price of a bottle of perfume is $40.16 if its original price was 50.07%.

What is discount?

By paying a charge or fee, a debtor might purchase the right to postpone payments to a creditor for a predetermined length of time through the financial mechanism known as discounting. In essence, the party who is currently owing money purchases the right to postpone payment until a later time.

Let the original price of the perfume bottle is, $50.07

The sale on the cosmetics is 19.8%.

So, the discount on the perfume bottle is,

50.07 x 0.198 = 9.91368

Therefore, the sale price of perfume is,

$50.07 - $9.91368 = $40.15614

Hence, the sale price of perfume is, $40.16

To know more about discount, click on the link

brainly.com/question/7459025

#SPJ4

7 0
1 year ago
What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction? Take the square root of both
balu736 [363]

Answer:

The first step is

Take the square root of both sides of the equation

Step-by-step explanation:

we have

x^{2} =\frac{9}{16}

Solve for x

step 1

Take square root both sides

x=(+/-)\frac{3}{4}

the solutions are

x=+\frac{3}{4} and  x=-\frac{3}{4}

therefore

The first step is

Take the square root of both sides of the equation

5 0
3 years ago
Read 3 more answers
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