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KonstantinChe [14]
3 years ago
15

Whats the standard deviation of 1,5,7,3,2,9,1

Mathematics
1 answer:
steposvetlana [31]3 years ago
7 0

Answer:

The pattern is see is saying

Step-by-step explanation: 5+2-4-1+7-8

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What is the common factor of the numerator and denominator in the expression <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%282x%2
mixer [17]

Answer:

Step-by-step explanation:

(x - 4)

What you are being asked to do is find the exact same binomial in the top as is in the bottom.

But there's a small catch. You must stipulate that x cannot equal 4. If it does, then you will get 0/0 which is undefined. You can't have that happening -- not at this level.

Any other value for x is fine.

5 0
3 years ago
Subtract 8-4 1/2. A. 3 B. 4 C. 4 1/2 D. 3 1/2
kicyunya [14]
This was the answer I came up with - 3.5
3 0
3 years ago
15pts<br> f(x)=(x+6)/2<br> g(x)=2x - 6<br> Show your work to evaluate g(f(x)).
notsponge [240]

Answer:

g(f(x)) = -x - 18

Step-by-step explanation:

2x - 6( (x + 6) / (2) )

2x - 3( x + 6)

2x - 3x - 18

-x - 18

4 0
3 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
Need answer to. Add 3x-3and4x^2-6x
Dahasolnce [82]
3x-3+4x^2-6x
4x^2-6x+3x-3 (arrange them in order)
4x^2-3x-3

do u want  more simplified form ?
7 0
3 years ago
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