Answer:
Solution given:
f(x)=x²
g(x)=x+5
h(x)=4x-6
now
23:
(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25
24:
(gof)(x)=g(f(x))=g(x²)=x²+5
25:
(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36
26:
(hof)(x)=h(f(x))=h(x²)=4x²-6
27;
(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1
28:
(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14
Given: Triangle JKL is dilated from the origin at a scale factor of 10 to create triangle J′K′L′.
Required: Correct option that complete the statement.
Explanation:
Now, triangle is dilated from the origin at a scale factor of 10.
So, the sides will become larger, but angles will remain the same.
Hence, the triangles will be similar as sides will be in proption (SSS rule).
So, The triangles are similar because their corresponding sides are proptional and their corresponding angles are congurent.
Final Answer: Second group is correct answer.
<em>Answer:</em>
<em>The net speed per 24 hours is 5 - 4 = 1 foot. </em>
<em>1 ft / 24 hrs = 16 ft / x hrs </em>
<em>
</em>
<em>16 * 24 hrs = 16 days (384 hrs)
</em>
<em />
Answer:
v = -8i - 6j
Step-by-step explanation:
The starting point is (9, 9)
The direction of the vector is the direction of the arrowhead.
The i is the horizontal component.
The j is the vertical component.
Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).
Therefore, v = -8i - 6j
