Question

If f(x) = |x| + 9 and g(x) = –6, which describes the range of (f + g)(x)? (f + g)(x) 3 for all values of x (f + g)(x) 3 for all values of x (f + g)(x) 6 for all values of x (f + g)(x) 6 for all values of x

Answer 1

Answer:

The range of values of $(f + g)(x) \ge 3$ is for all values of x $-\infty$ to $+\infty$

Step-by-step explanation:

Given

$f(x) = |x| + 9$

$g(x) = -6$

Required

Describe the range of $(f+g)(x)$

First, calculate $(f+g)(x)$

$(f+g)(x) = f(x) + g(x)$

Substitute values for f(x) and g(x)

$(f+g)(x) = |x| + 9 -6$

Evaluate Like Terms

$(f+g)(x) = |x| + 3$

The above expression shows that $(f + g)(x) \ge 3$

Because $|x| \ge 0$

Hence, the range of values of $(f + g)(x) \ge 3$ is for all values of x $-\infty$ to $+\infty$

Answer 2

Answer:

A

Step-by-step explanation:

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