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Vitek1552 [10]
2 years ago
8

Four friends go to the movies and split the total cost between them the total is 17.28 for movie tickets and 13.68 for snacks ho

w much should each of them pay ?
A) 7.77
B)7.74
C)10.32
D)30.96
Mathematics
1 answer:
Pavel [41]2 years ago
3 0
The answer is: D 30.96.

Hope this helps! (:
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A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

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A rectangular football field is 64 meters wide and 100 maters long. A player runs from one corner of the field in a diagonal lin
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Answer:

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Step-by-step explanation:

We should use the Pythagorean Theorem to solve this problem.

a^2+ b^2=c^2

64^2+100^2=c^2

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c^2=14096

c=\sqrt{14096}14096

And the root of 14096 is 118.726577.

So the Answer is About 119 meters, or 118.726577

hope this helps!

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