Answer:
2 non real solutions.
Step-by-step explanation:
We need to use discriminant,
for ax²+bx+c=0
The discriminat is b²-4ac
If the discriminant is,
→ less than 0, then 0 real solutions
→ equal to 0, then 1 real solutions
→ more than 0, then 2 real solutions
Given that,
7x²−4x+3=0
a=7, b=-4, and c=3
→ (-4)²-4(7)(3)
→ 16-84
→ -68
You can see this is less than 0, then non real solutions. [2 nonreal solutions]
X=-1 is the answer. Hope that helps!
7(a - 10) = 13 - 2(2a + 3)
7a - 70 = 13 - 4a - 6 = 7 - 4a
7a + 4a = 7 + 70
11a = 77
a = 77/11 = 7
a = 7.
Correct answer is the one you put
