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neonofarm [45]
2 years ago
14

1. The diagonal of a quadrilateral

Mathematics
1 answer:
zalisa [80]2 years ago
6 0

Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.

Given:

Length of the diagonal of a quadrilateral = 8.5 cm

Lengths  of the perpendiculars dropped on  it from the remaining opposite  vertices are 3.5 cm and 4.5 cm.

To find:

The area of the quadrilateral.

Solution:

Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths  of the perpendiculars dropped on  it from the remaining opposite  vertices are heights of those triangles.

According to the question,

Triangle 1 :  Base = 8.5 cm and Height = 3.5 cm

Triangle 2 :  Base = 8.5 cm and Height = 4.5 cm

Area of a triangle is

Area=\dfrac{1}{2}\times base \times height

Using this formula, we get

Area(\Delta 1)=\dfrac{1}{2}\times 8.5\times 3.5

Area(\Delta 1)=14.875

and

Area(\Delta 2)=\dfrac{1}{2}\times 8.5\times 4.5

Area(\Delta 2)=19.125

Now, area of the quadrilateral is

Area=Area(\Delta 1)+Area(\Delta 2)

Area=14.875+19.125

Area=34

Therefore, the area of the quadrilateral is 34 cm².

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It's asking "what number can we add to both sides of this equation so that we isolate x?"

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Answer:

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Step-by-step explanation:

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