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4 years ago

How to do 8 7/10 minus 5 9/10

Mathematics

2 answers:

RoseWind [281]4 years ago

8 0

8 7/10= 87/10

5 9/10= 59/10

87/10-59/10= 28/10=2 4/5

Murljashka [212]4 years ago

4 0

I think it's gonna be 2/6 I don't know if it's right

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Please answer the questions

siniylev [52]

Answer:

root (7²+8²)=10.63
root (10²-5²)=8.66
root (11²-3²)=10.58
root (18²+15²)=23.43

Step-by-step explanation:

a²+b² = c²

a = side of right triangle

b = side of right triangle

c = hypotenuse

6 0

3 years ago

I need help with this problem someone please help me

tatuchka [14]

Answer:

180-46=134

134/2=67

8 0

3 years ago

Read 2 more answers

The ratio of petunias to geraniums in the greenhouse was 15 to 2. The combined numbernof petunias and geraniums was 1020.

AnnZ [28]

Answer:

E. 120

Step-by-step explanation:

Let's say the number of total flowers is (15+2)x

That means the number of geraniums is 2x.

That also means that 1020 = 17x, which makes x = 60

Because 2x = geraniums and x = 60, the number of geraniums is 120

8 0

3 years ago

What number should be added to both sides of the equation to complete the square?

lubasha [3.4K]

Answer:

9 should be added to both sides of the equation to complete the square.

Step-by-step explanation:

Given : $x^2 -6x = 5$

To Find: What number should be added to both sides of the equation to complete the square?

Solution:

$x^2 -6x = 5$

Add the square of half of coefficient of x

So, the square of half of coefficient of x = $(\frac{6}{2})^2=3^2 =9$

So, $x^2 -6x +9 = 5+9$

$x^2 -6x +3^2 = 5+9$

$x^2 -2 \times 3 \times x +3^2 = 5+9$

$(x-3)^2 = 5+9$

$(x-3)^2 =14$

Thus 9 should be added to both sides of the equation to complete the square.

8 0

3 years ago

What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE

Nutka1998 [239]

Answer:

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),$ $\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

Step-by-step explanation:

Let points D, E and F have coordinates $(x_D,y_D),\ (x_E,y_E)$ and $(x_F,y_F).$

1. Midpoint M of segment DF has coordinates

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).$

2. Midpoint N of segment EF has coordinates

$\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0

3 years ago