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3 years ago

Assessment: Solve Me!

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

5 0

Answer:

1 . option b

2. option d

Step-by-step explanation:

1) Diameter = 8cm

Radius = 8/2 = 4cm

2) Diameter = 8cm

Radius = 4cm

$Volume = \frac{1}{3} \pi r^2h = \frac{1}{3} \pi 4^2 \times 15 = 16 \pi \times 5 = 80 \pi = 251.2cm^3$

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If f(x) = -2x + 8 and g(x) = x + 7, what is<br> F•g)(2)?

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16•7•2 is not the answer

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3 years ago

20. A cement mixer held 6 3/4 tons of cement. Ms. Folley used 2/3 of the cement for her driveway. How many tons of cement remain

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Answer:

6 2/25 tons cement

Step-by-step explanation:

If cement mixer held 6 3/4 tons=6.75 tons

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So,

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2 years ago

Use a whole number, a fraction, one plus sign, and four 2's to make 23.

alexira [117]

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3 years ago

Alia has a AED 20 gift card for an online music store. All songs at the store have the same price. After Alia buys 3 songs, the

sladkih [1.3K]

Answer:

Remaining balance = AED 13.75

Step-by-step explanation:

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Hence,

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3 years ago

A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

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3 years ago