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Flura [38]
2 years ago
8

211,207,203,... Find the 38th term.

Mathematics
1 answer:
dsp732 years ago
8 0

Answer:

63

Step-by-step explanation:

Using the formula attached, we can setup the equation:

211 + (38 - 1) - 4

Then using a calculator you can solve

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Can y’all help me please
matrenka [14]

Answer:

w = 5

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

28 = 2(2w-1 + w)

Combine like terms

28 =2(3w-1)

Divide each side by 2

28/2 = 2/2(3w-1)

14 = 3w-1

Add 1 to each side

14+1 = 3w-1+1

15 = 3w

Divide each side by 3

15/3 =3w/3

5 =w

8 0
3 years ago
What is the horizontal asymptote of mc001-1.jpg?<br> y = –2<br> y = –1<br> y = 0<br> y = 1
Y_Kistochka [10]
The answer is the first options: y=-2

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3 0
3 years ago
Read 2 more answers
Which of the following equations correctly represents the law of cosines?
dusya [7]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
I HAVE A CYLINDER AND cone WITH THE
Vlad1618 [11]

Answer:

99 in³

Step-by-step explanation:

Let the radius and height of each be r and h in. respectively.

Write an equation for the volume of cone.

Volume of cone= ⅓πr²h

⅓πr²h= 33

Multiply both sides by 3:

πr²h= 99

Volume of cylinder= πr²h

We have found the value of πr²h previously, which is 99.

Thus, the volume of the cylinder is 99 in³.

6 0
2 years ago
The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe
WARRIOR [948]

Answer:

7536 km^3/sec

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

Volume = \pi r^2h

Where r is the radius and

h is the height of cylinder.

As per question statement:

r = 40 km (variable)

h = 2.5 (constant)

\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h

As \pi, h are constant:

\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec

4 0
3 years ago
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