Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
Step-by-step explanation:
The surface area of a sphere with radius r is given by
S = 4 pi r^2
for a radius of 11 units,
S = 4 pi 11^2 = 484 pi = 1520.5 sq. units
This does not correspond to any of the answers.
Please check question.
Answer:
Step-by-step explanation:
The equation of a line in the point-slope form:
We have:
Substitute:
Answer:
( 7x + 11 )( 7x- 11 )
Step-by-step explanation:
( 7x + 11 )( 7x- 11 )
Because 7*7 is 49
-11*11= -121
7*11=77
-7*11= -77
77-77=0
so the answer is 49x^2-121
