Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
Answer:
C
Step-by-step explanation:
Recall the equation for a circle:
, where the center is (h,k) and the radius is r.
The given equation is:

Another way to write this is:

Thus, we can see that h=-5 and k=-7.
The center is at (-5, -7).
Answer:(12,-7)
Step-by-step explanation:
The pool has a diameter 20 ft so: r = 10 ft.
The pool cover extents 12 inches beyond the edge of the pool.
12 inches = 1 foot
Therefore, the radius of the pool cover is : r = 10 + 1 = 11 ft.
a. The area of the pool cover:
A = r² π = 11² π = 121 π ft²
b. The length of the rope:
l = 2 r π = 2 · 11 π = 22 π ft.