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labwork [276]
3 years ago
15

The center of the circle is A( -3,3) and B(1,6) is on the circle. Find the area of the circle in terms of pie

Mathematics
1 answer:
Verdich [7]3 years ago
3 0
We'll need to find the equation of this circle.  Once we have that equation, we use r to calculate the area.

The general equation of a circle with center at (h,k) and radius r is

(x-h)^2 + (y-k)^2 = r^2.  Subst. the given info (-3,3) [center] and (1,6) [point on circle], we get

(x+3)^2 + (y-3)^2 = r^2

(1+3)^2 + (6-3)^2 = r^2

16 + 9 = 25 = r^2

The area of this circle is A =pi(r^2).  But r^2 = 25.  So the area is

A = pi(25), or   A = 25pi.   Please note:  it's "pi," not "pie."
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What is 2000 dividable by​
kirill115 [55]

Answer:

1

Step-by-step explanation:

everything is!!!

4 0
3 years ago
please help will get rewared with brainliest ad 5 stars if correct answer please help struggling in school rn
serg [7]

Answer: Yes that I correct.

Step-by-step explanation:

Because 25 times 4 is 100 and what you do to the bottom you have to do to the top so 7 times 4 is 28

8 0
3 years ago
Extra Credit #4
Hunter-Best [27]

Answer:

The next two numbers following:

431

141311

1114111321

311431131211

are:

132114132113111221

AND

11131221141113122113312211

Step-by-step explanation:

I shall explain the pattern below:

431 (just the digits 4, 3, and 1)

141311 (one 4 becomes 14, one 3 becomes 13, one 1 becomes 11 -> looking at each digit of the previous number, 431)

1114111321 (one 1 becomes 11, one 4 becomes 14, one 1 becomes 11, one three becomes 13, two consecutive 1s becomes 21 -> looking at each digit of the previous number, 141311)

311431131211 (three consecutive 1s becomes 31, one 4 becomes 14, 3 more consecutive 1s becomes 31, one 3 becomes 13, one 2 becomes 12, and one 1 becomes 11 -> looking at each digit of the previous number, 1114111321)

NEXT TWO NUMBERS:

one 3 (13), two consecutive 1s (21), one 4 (14), one 3 (13), two consecutive 1s (21), one 3 (13), one 1 (11), one 2 (12), two consecutive 1s (21)

that makes: 132114132113111221

one 1 (11), one 3 (13), one 2 (12), two consecutive 1s (21), one 4 (14), one 1 (11), one 3 (13), one 2 (12), two consecutive 1s (21), one 3 (13), three consecutive 1s (31), two consecutive 2s (22), one 1 (11)

that makes: 11131221141113122113312211

The rule is that the next number is essentially the previous number with the number of times each digit appears consecutively before each digit of the previous number. I know that sounds convoluted. Hopefully it makes enough sense. Let me know if I should explain more fully.

8 0
3 years ago
Use the distributive property to express 40 in a different form.
Artemon [7]

Answer:

5(4 + 4)

Step-by-step explanation:

5(4 + 4)

20 + 20

40

Hope this helps!

=)

4 0
3 years ago
Calculate the length of the hypotenuse
Colt1911 [192]

hypotenuse =sqrt( a^ + b^

10^2 = 100

14^2 = 196

196+100 = 296

 sqrt(296) = 17.20

 Answer is D. 17.20

7 0
3 years ago
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