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telo118 [61]
3 years ago
5

What is the sum (2/5 x +5/8)+(1/5 x - 1/4)?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

\left(\dfrac{2}{5}x+\dfrac{5}{8}\right)+\left(\dfrac{1}{5}x-\dfrac{1}{4}\right)=\left(\dfrac{2}{5}x+\dfrac{1}{5}x\right)+\left(\dfrac{5}{8}-\dfrac{1}{4}\right)\\\\=\dfrac{2+1}{5}x+\left(\dfrac{5}{8}-\dfrac{1\cdot2}{4\cdot2}\right)=\dfrac{3}{5}x+\left(\dfrac{5}{8}-\dfrac{2}{8}\right)\\\\=\dfrac{3}{5}x+\dfrac{5-2}{8}=\boxed{\dfrac{3}{5}x+\dfrac{3}{8}}

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Anna007 [38]

Answer:

(x - 5)(x + 8)

Step-by-step explanation:

Your equation is: x² + 3x - 40

1. Factor the quadratic

(a) Find two numbers that multiply to give -40 and add to give 3.

List the positive factors of 40: 1, 2, 4, 5, 8, 10, 20, 40

One of the numbers must be negative. Start with the numbers near the middle of the list.

By trial and error, you will find that +8 and -5 work:

-5 × 8 = -40 and -5+8 = 3

(b) Rewrite 3x as -5x + 8x

x² - 5x + 8x - 40

(c) Factor the first two and the last two terms

x(x - 5) + 8(x - 5)

(d) Separate the common factor

x² + 3x - 40  = (x - 5)(x + 8)

2. Using Desmos

You can plot the equation with Desmos.

You get a parabola with x-intercepts at x = -8 and x = 5.

These are the solutions to

x + 8 =0 and x - 5 = 0, so

x² + 3x - 40 =  (x+ 8)(x - 5)

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