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mihalych1998 [28]
3 years ago
5

There are approximately 2.6 million deaths per year in country A. Express this quantity as deaths per minute.

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
7 0
Take 2.7 million<span> divided </span>by<span> the number of </span>minutes<span> in a </span>year<span>. 1 hour= 60 </span>minutes<span> 1 day= 24 hours So you take 24 hours × 60 minutes =1440 </span>minutes<span> 1 </span>year<span>= 365 per minute.</span>
solniwko [45]3 years ago
7 0
In one year, there are 365  days 
                   365x24=8760  hours
        8760x60=525 600 minutes

Dividing 2.6 million to the last number (525 600), we find death per minute in this country, which gives us more than 4 deaths in a minute. 
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Answer:

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Step-by-step explanation:

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2 years ago
A rectangular solid has width w, a length of 7 more than the width, and a height that is equivalent to 15 decreased by 3 times t
dexar [7]

Answer:

For a rectangular solid with:

width = w

length = l

height = h

The volume is equal to:

V = w*l*h

in this case we know that:

width = w.

"length of 7 more than the width"

l = w + 7.

"a height that is equivalent to 15 decreased by 3 times the width."

h = 15 - 3*w

Then the volume will be:

V = w*l*h = w*(w + 7)*(15 - 3w) = (w^2 + 7*w)*(15 - 3*w)

V =  ( -3*w^3 + 15*w^2 + 105*w - 21*w^2)

V = (-3*w^3 - 6*w^2 + 105*w)

Now, the maximum volume will be for the value of w such that:

V'(w) = 0.

and:

V''(W) < 0

Where:

dV/dw = V'(w).

dV'/dw = V''(w)

Then first we need to differentiate the equation for the volume.

V'(w) = dV/dw = ( 3*(-3*w^2) + 2*(-6*w) + 105)

V'(w) = -9*w^2 - 12*w + 105.

Then we need to find the solution for:

-9*w^2 - 12*w + 105 = 0.

We can use the Bhaskara formula, and we will get:

w = \frac{+12 +-\sqrt{(-12)^2 - 4*(-9)*105} }{2*-9}  = \frac{+12 +- 62.6}{-18}

Then the two solutions are:

w₁ = (+12 - 62.6)/(-18) = 2.81

w₂ = (+12 + 62.6)/(-18) = -15.5

But we can not have a negative width, so we can just discard the second solution.

Now let's check the second condition for the maximum, we must have:

V''(2.81) < 0.

V'' = dV'/dw = 2*(-9*w) - 12 = -18*w - 12

V''(2.81) = -18*2.81 - 12 = -62.58 < 0 .

Then the volume is maximized when w = 2.81, and the maximum volume will be:

V(2.81) =  (-3*(2.81)^3 - 6*(2.81)^2 + 105*2.81) = 180.1

 

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3 years ago
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Tema [17]

Answer:

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Step-by-step explanation:

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3 years ago
A circular pool measures 10 feet across. one cubic yard of concrete is to be used to create a circular border of uniform width a
mina [271]

we know that

1 ft is equal to 12 in

1 cubic yard is equal to 27 cubic​ feet

Step 1

<u>Find the area of the circular border of uniform width around the pool</u>

Let

x---------> the uniform width around the pool    

we know that

The diameter of the circular pool measures 10 feet

so

the radius r=5 ft

the area of the circular border is equal to

A=\pi *(5+x)^{2}- \pi *5^{2} \\A= \pi *[(x+5) ^{2}-5^{2} ] \\ A= \pi * [x^{2} +10x]

step 2

volume of the concrete to be used to create a circular border is equal to

V=1 yd^{3}-------> convert to ft^{3}

V=27 ft^{3} -------> equation 1

the depth is equal to 4 in-------> convert to ft

depth=4/12=(1/3) ft

volume of the concrete to be used to create a circular border is also equal to

V=Area of the circular border*Depth

V= \pi * [x^{2} +10x]*(1/3) -------> equation 2

equate equation 1 and equation 2

27=\pi * [x^{2} +10x]*(1/3) \\ x^{2} +10x- \frac{81}{\pi }=0

using a graph tool------> to resolve the second order equation

see the attached figure

the solution is the point

x=2.126 ft

therefore

<u>the answer is</u>

The uniform width around the circular pool border is 2.126 ft

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