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Mice21 [21]
3 years ago
8

24 POINTS PLEASE

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

2.5X=1.0 try this i think

Step-by-step explanation:

tRY THAT

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Cos(x-30°)=0 <br> how???????????????
lesya [120]

Answer:

Step-by-step explanation:

I'm assuming you're trying to solve this for x. We use the difference identity for cosine and rewrite:

cos(x-30)=cosxcos30+sinxsin30 and simplify using the unit circle to help.

cosx(\frac{\sqrt{3} }{2})+sinx(\frac{1}{2})=0\\cosx(\frac{\sqrt{3} }{2})=-\frac{1}{2} sinx\\cosx=-\frac{1}{2}(\frac{2}{\sqrt{3} })sinx\\cosx=-\frac{1}{\sqrt{3} }sinx\\1=-\frac{1}{\sqrt{3} }\frac{sinx}{cosx}\\1=-\frac{1}{\sqrt{3} }tanx\\-\sqrt{3} =tanx

and on the unit circle, the angle where the tangent is negative square root of 3 is -60° which is also a positive 300°

8 0
3 years ago
Read 2 more answers
Help
WINSTONCH [101]
3ft and 11in is the correct answer
3 0
3 years ago
Read 2 more answers
What is the quotient if 2/4 of 40 is divided by 4/5 of 5/7?
timofeeve [1]

Answer:

2/4 * 40 4/5 * 5/7 = 102/

7

= 14 4/

7

≅ 14.5714286

Step-by-step explanation:

To find a new numerator:

a) Multiply the whole number 40 by the denominator 5. Whole number 40 equally 40 * 5/

5

= 200/

5

b) Add the answer from previous step 200 to the numerator 4. New numerator is 200 + 4 = 204

c) Write a previous answer (new numerator 204) over the denominator 5.

Forty and four fifths is two hundred four fifths

Multiple: 2/

4

* 204/

5

= 2 · 204/

4 · 5

= 408/

20

= 102 · 4/

5 · 4

= 102/

5

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(408, 20) = 4. In the following intermediate step, cancel by a common factor of 4 gives 102/

5

.

In other words - two quarters multiplied by two hundred four fifths = one hundred two fifths.

Multiple: the result of step No. 2 * 5/

7

= 102/

5

* 5/

7

= 102 · 5/

5 · 7

= 510/

35

= 102 · 5/

7 · 5

= 102/

7

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(510, 35) = 5. In the following intermediate step, cancel by a common factor of 5 gives 102/

7

.

In other words - one hundred two fifths multiplied by five sevenths = one hundred two sevenths.

7 0
2 years ago
List the integers that satisfy both these inequalities.
alekssr [168]

Answer: -12 < x < -\frac{9}{2}

<u>Step-by-step explanation:</u>

2x + 9 < 0    and      x > -12

2x       < -9

 x        < -\frac{9}{2}


Since it is an "and" statement, x is between -12 and -\frac{9}{2}, so -12 < x < -\frac{9}{2}

Graph: -12 o-----------------o -\frac{9}{2}

Interval Notation: (-12, -\frac{9}{2})

8 0
3 years ago
12(a +3)° +4(a+3) factorise​
atroni [7]

Answer:

16a+48

Step-by-step explanation:

(12+4)(a+3)

16(a+3)

16a+48

5 0
3 years ago
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