3 years ago

Don’t give me a website pls

1 answer:

4 0

C x=7 hop this helps you

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Rudik [331]

Answer:

a) E(y) = 0.8

b) The average subcharge is $165

Step-by-step explanation:

We are given the following distribution in the question:

y: 0 1 2 3

P(y): 0.50 0.25 0.20 0.05

a) E(y)

$E(y) = \displaystyle\sum y_iP(y_i)\\\\E(y) = 0(0.50)+1(0.25)+2(0.20)+3(0.05)\\E(y) = 0.8$

b) Expected value of subcharge

Subcharge =

$\$110y^2$

Expected value of subcharge =

$=110E(y^2)\\\\=110\displaystyle\sum y_i^2P(y_i)\\\\=110(0^2(0.50)+1^2(0.25)+2^2(0.20)+3^2(0.05))\\=110(1.5)=165$

Thus, the average subcharge is $165

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Ray Of Light [21]

Answer: By putting it on a graph

Step-by-step explanation:

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The weight can vary from 22.5 to 25.5

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vampirchik [111]

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