20 times 5 is 100. We can multiply 2*5 and get 10, then add another zero to make it easier.
Answer:
The rate of plane in still air is 834 km/hr and the rate of wind is 80 km/hr.
Step-by-step explanation:
The airplane travels 6032 km in 8 hours against the wind.
So,
........ (1) {Where u is the speed of plane in still air and v is the wind speed}
Again, the airplane travels 7312 km in 8 hours with the wind.
So,
........ (2)
Now, adding equations (1) and (2) we get,
2u = 1668
⇒ u = 834 km per hour.
So, from equation (1), we get
v = u - 754 = 834 - 754 = 80 km per hour.
Therefore, the rate of the plane in still air is 834 km/hr and the rate of wind is 80 km/hr. (Answer)
Answer:
The correct option is D) 
Step-by-step explanation:
Consider the provided information.
People are entering a building at a rate modeled by f (t) people per hour and exiting the building at a rate modeled by g (t) people per hour,
The change of number of people in building is:

Where f(t) is people entering in building and g(t) is exiting from the building.
It is given that "The functions f and g are non negative and differentiable for all times t."
We need to find the the rate of change of the number of people in the building.
Differentiate the above function with respect to time:
![h'(x)=\frac{d}{dt}[f(t)-g(t)]](https://tex.z-dn.net/?f=h%27%28x%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Bf%28t%29-g%28t%29%5D)

It is given that the rate of change of the number of people in the building is increasing at time t.
That means 
Therefore, 
Hence, the correct option is D) 
A Hexagon Is A 6 Sided Figure. So First, We Need To Know How Many Centimeters Are In A Meter. There Are 100 Centimeters In A Meter. Next, Do 2 Meters * 100 centimeters To Get 2 Meters Is Equal To 200 Centimeters. Next, We Do 35*6. We Get 210. Now, Do The Subtraction. 210-200 = 10cm. The Regular Hexagon's Perimeter Is 10cm Larger. I Hope I Helped! :D