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2 years ago

In what year did WW1 begin

Mathematics

2 answers:

creativ13 [48]2 years ago

7 0

Answer:

It started on: July 28, 1914

Step-by-step explanation:

It ended on – November 11, 1918

Fynjy0 [20]2 years ago

4 0

Answer:

28 July 1914 – 11 November 1918

please mark me brilliant

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The hypotenuse of a right triangle measures 16 cm and one of its legs measures 11 cm.

Zarrin [17]

Answer:

11.6cm

Step-by-step explanation:

a^2+b^2=c^2

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2 years ago

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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2 years ago

Solve the x <br> 1/3x + 5> 10

kotykmax [81]

Answer:

The solution to the inequality is:

$\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}$

The solution graph is also attached below.

Step-by-step explanation:

Given

We are given the expression

$\frac{1}{3}x+5>10$

To determine

Solve for x

Given the expression

$\frac{1}{3}x+5>10$

Subtract 5 from both sides

$\frac{1}{3}x+5-5>10-5$

Simplify

$\frac{1}{3}x>5$

Multiply both sides by 3

$3\cdot \frac{1}{3}x>5\cdot \:3$

Simplify

$x>15$

Thus, we conclude that:

$x>15$

Therefore, the solution to the inequality is:

$\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}$

The solution graph is also attached below.

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2 years ago