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bogdanovich [222]
3 years ago
14

Please help me tell whether each function is a linear or quadratic, thank you!

Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

first one is linear and second is quadratic.

Step-by-step explanation:

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Evaluate the determinant for the following matrix [3 -5 / 1 1]
Natalka [10]

Answer:

<h2>A. -2</h2>

Step-by-step explanation:

\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2

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C

Step-by-step explanation:

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Please answer asap!!!! will mark brainiest
Inga [223]

Answer:

x=2

Step-by-step explanation:

We know the only number that gets us back to 0 after subtracting 4 is 4, because 4-4=0. The square root of 4 is 2. Hope my explanation wasn't too confusing!

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Find the greatest common factor of 210, 84, and 56
mr Goodwill [35]
To get the Greates Common Factor (GCF) of 84 and 210 we need to factor each value first and then we choose all the copies of factors and multiply them: 

<span><span>84:   223 7</span><span>210:   2 357</span><span>GCF:   2 3 7</span></span>

<span>The Greates Common Factor (GCF) is:   2 x 3 x 7 = 42</span>

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An ice chest contains cans of apple juice, cans of grape juice, cans of orange juice, and cans of mango juice. Suppose that you
mel-nik [20]

Answer:

4.9%

Step-by-step explanation:

This question is incomplete. However; it can be found on search engines. The complete question is  as follows :

An ice chest contains cans of six apple juice, eight cans of grape juice, four cans of orange juice, and two cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting three cans of grape juice.

Solution :

In an ice chest there are different cans of juice. Among them

Number of cans of apple juice = 6

Number of cans of grape juice = 8

Number of cans of orange juice = 4

Number of cans of mango juice = 2

Total number of cans of juice = 6 + 8 + 4 + 2 = 20

Let A, B and C are the event of selecting of three cans.  The events A, B and C are dependent.

Probability of selecting three cans of juice

P = \frac{\text{number of grape cans}}{\text {total number of cans}}

P (A) = \frac{8}{20}

P (B) = \frac{7}{19}

P (B) = \frac{6}{18}

P = \frac{8}{20} × \frac{7}{19} × \frac{6}{18}

  = \frac{336}{6840}

  = 0.049 or 4.9%

Probability of selecting three cans of grape juice is 4.9%

5 0
3 years ago
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