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Nutka1998 [239]

3 years ago

8

ALGEBRA 1:

1 answer:

tekilochka [14]3 years ago

8 0

Answer:

27x to the power of 3 minus 27x to the power of 2 plus 69x minus 21

Step-by-step explanation:

hope this helps

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The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

zavuch27 [327]

Answer:

(–1, 1)

(4, –2)

Step-by-step explanation:

Let

(x,y) ----> the coordinates of point C

Applying the Pythagoras Theorem

$(-1-4)^2+(-2-1)^2=(x-4)^2+(y-1)^2+(x+1)^2+(y+2)^2$

step 1

Find the possibles values of x

$(-1-4)^2=(x-4)^2+(x+1)^2\\\\25=x^{2}-8x+16+x^{2}+2x+1\\\\2x^{2}-6x-8=0$

Simplify

$x^{2}-3x-4=0$

Solve the quadratic equation

$x^{2}-3x-4=(x+1)(x-4)$

The values of x are

x=-1 and x=4

step 2

Find the possibles values of y

$(-2-1)^2=((y-1)^2+(y+2)^2\\\\9=y^{2}-2y+1+y^{2}+4y+4\\\\2y^{2}+2y-4=0$

Simplify

$y^{2}+y-2=0$

Solve the quadratic equation

$y^{2}+y-2=(y+2)(y-1)$

The values of y are

y=-2, y=1

therefore

The possibles coordinates of point C are

(-1,1),(4,-2)

3 0

3 years ago

Read 2 more answers

Whet is 2y+14x-7x+9y

matrenka [14]

Answer:

Step-by-step explanation:

2y + 14x - 7x + 9y

2y + 9y + 14x - 7x

11y + 7x

6 0

3 years ago

Read 2 more answers

Darren invests $4,500 into an account that earns 5% annual interests. How much will be in the account after 10 years if the inte

Tom [10]

We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$5\%=\frac{5}{100}=0.05$

When compounded annually, $n=1$ :

$A=4500(1+\frac{0.05}{1})^{1\cdot 10}$

$A=4500(1.05)^{10}$

$A=4500(1.6288946267774414)$

$A=7330.025820498\approx 7330.03$

When compounded quarterly, $n=4$ :

$A=4500(1+\frac{0.05}{4})^{4\cdot 10}$

$A=4500(1.0125)^{40}$

$A=4500(1.6436194634870132)$

$A=7396.28758569\approx 7396.29$

When compounded monthly, $n=12$ :

$A=4500(1+\frac{0.05}{12})^{12\cdot 10}$

$A=4500(1.00416666)^{120}$

$A=4500(1.64700949769)$

$A=7411.542739605\approx 7411.54$

When compounded daily, $n=365$ :

$A=4500(1+\frac{0.05}{365})^{365\cdot 10}$

$A=4500(1.0001369863013699)^{3650}$

$A=4500(1.6486648137656943695)$

$A=7418.9916619456\approx 7419.00$

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

3 0

3 years ago

Write the equation of the tangent line to x2+y2=41 at the point (-4,5)

AnnyKZ [126]

Answer:

As attached

Step-by-step explanation:

6 0

3 years ago

Reflection Lines

mel-nik [20]

Answer:

Midpoint

Step-by-step explanation:

Equidistant from the pre = image AA would be the middle

3 0

3 years ago