Question

A restaurant owner has found that 80% of her customers return to the restaurant within two weeks. She wants to create a tool that will simulate the habits of her customers and allow her to predict the probability that three of the next four customers to visit her restaurant will return within two weeks.

Answer 1

I believe the problem ask for the appropriate spinner simulation device to use among the choices. The given choices are:

1. a spinner divided into 5 congruent sectors, spun 3 times

2. a spinner divided into 5 congruent sectors, spun 4 times

3. a spinner divided into 2 congruent sectors, spun 3 times

4. a spinner divided into 2 congruent sectors, spun 4 times

 

The correct spinner to use among the 4 should have a probability of winning of 80%, similar to what the owner has found out. So, we must calculate the probability of each spinner.

 

1. Spun 3 times, and chance of winning is 1 in 5, therefore P = (3) (1/5) = 0.6 = 60%

2. Spun 4 times, and chance of winning is 1 in 5, therefore P = (4) (1/5) = 0.8 = 80%

3. Spun 3 times, and chance of winning is 1 in 2, therefore P = (3) (1/2) = 1.5 = 150%

4. Spun 4 times, and chance of winning is 1 in 2, therefore P = (4) (1/2) = 2 = 200%

 

We can see that there is only 1 choice that has 80% probability, therefore the correct answer is:

 

“a spinner divided into 5 congruent sectors, spun 4 times”

Answer 2

Answer:

(B) a spinner divided into 5 congruent sectors, spun 4 times

Step-by-step explanation: