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vampirchik [111]
3 years ago
9

Find the value of x please I need help

Mathematics
2 answers:
s2008m [1.1K]3 years ago
4 0

Answer:

Step-by-step explanation:

113+90+90+12x+7=360(sum of four angles is always 360 degree)

300+12x=360

12x=360-300

x=60/12

x=5

elena55 [62]3 years ago
3 0

Answer:

X = 5

Step-by-step explanation:

Shapes with 4 sides have angles that add to 360 degrees

So you have two right angles and 113 degrees.

This is

90+90+113=293

360-293=67

12x5=60

60+7=67

This means that x=5

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The nth term of a sequence is 20 - n2
maks197457 [2]

Answer:

11

Fifth term

Step-by-step explanation:

The third term is:

20 − (3)² = 11

If the term is negative:

20 − n² < 0

n² > 20

n > √20

n > 4.47

The first term to have a negative value is the fifth term.

5 0
3 years ago
Which function represents the graph of f(s)=-4[x] after it is translated 3 units down?
MaRussiya [10]
I'm not sure but I think, f(s)=-4[x]-3
8 0
3 years ago
Simply the following 2m⁵×5m³×7m²​
Ganezh [65]

Answer:

2m^5\cdot 5m^3\cdot 7m^2=70\cdot m^{10}

Step-by-step explanation:

Simplify the expression

2m^5\cdot 5m^3\cdot 7m^2

Calculate the product of the coefficients:

2*5*7=70

Compute the product of the variables. Since they are all the same letter, sum their exponents:

m^5\cdot m^3\cdot m^2=m^{5+3+2}=m^{10}

Combine the results:

\boxed{2m^5\cdot 5m^3\cdot 7m^2=70\cdot m^{10}}

3 0
3 years ago
Which number is halfway between
Anarel [89]
You are looking for the average. To find the average, one adds all terms and divides by the number of terms.
((1/2)+(5/6))/2
((3/6)+(5/6))/2
(8/6)/2
(4/6)
(2/3)
The answer is B) 2/3.
6 0
3 years ago
A sample of gold has a mass of 579 g. The volume of the sample is 30 cm3. What is the density of the gold sample?
Ugo [173]

The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

V = 30 cm³

Let the density of the gold sample be represented by ρ

The formula for the density is:

Density = \frac{Mass}{Volume}

\rho = \frac{m}{V} \\\rho = \frac{579}{30} \\\rho = 19.3 g/cm^3

The density of the gold sample is 19.3g/cm³

Learn more here: brainly.com/question/17780219

3 0
3 years ago
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