Answer:
with what may I help you with
Step-by-step explanation:
<span>2≤x≤8</span>
<span>−4≤<span>f′</span>(x)≤5</span>
f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that
<span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span>
And we know
<span>−4≤<span>f′</span>(c)≤5</span>
=> we have
<span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
<span>x greater than or equal to −4 and x less than or equal to 3
This is because of the fact that it is in between.</span>
Answer:
1. B) 7
2. B) {y|y ≤ -1}
Step-by-step explanation:
1. Put -4 where x is in the function definition and do the arithmetic.
... 3 - (-4) = 3 +4 = 7
2. If the maximum function value is -1 and the values extend to -∞ from there, then the range is (-∞, -1]. In your notation, that is ...
... {y | y ≤ -1}
Answer:
No, it is not a irrational number
