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12345 [234]
3 years ago
9

Determine whether each expression is equivalent to 10^t^2+2t-3

Mathematics
1 answer:
deff fn [24]3 years ago
4 0

All answer choices are equivalent

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What is the lcd of: 8/9x 2/3x=1/9x 45?
spayn [35]
LCD would be 18

8/9 = 16/18
2/3 = 12/18
1/9 = 2/18
5 0
3 years ago
Karl is putting a frame around a rectangular photograph. The photograph is 14 inches long and 10 inches wide, and the frame is t
Sergeu [11.5K]
<h2>The area of the framed photograph = 1156 inch^{2}</h2>

Step-by-step explanation:

Given,

The length of photograph (l) = 14 inches and

The breadth of photograph (b) = 10 inches

To find, the area of the framed photograph = ?

We know that,

The area of the framed photograph = (l + 2b)(l + 2b)

= (14 + 2 × 10) (14 + 2 × 10) inch^{2}

= (14 + 20) (14 + 20) inch^{2}

= (34) (34) inch^{2}

= 1156 inch^{2}

∴ The area of the framed photograph = 1156 inch^{2}

8 0
3 years ago
Will give brainliest to correct answer please help
tangare [24]

Answer:

Its B

Step-by-step explanation:

I did the test on edge

6 0
3 years ago
Select all the relationships that demonstrate a positive association between variables.
Stells [14]

Answer:

O.Length of time you have walked and distance you have traveled.

O.Pounds of cherries you buy and amount of money you spend on cherries.

O.Number of people in a grocery check-out line and how long you have to wait to check out

Step-by-step explanation:

Please tell me this is correct and if it isn't I'm sorry if it is please mark Brainliest!

6 0
3 years ago
The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.​
erma4kov [3.2K]

Answer:

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm

\\

Step-by-step explanation:

Given:

  • Radius of the cylinder = 7 cm
  • Height of the cylinder = 10 cm

\\

To Find:

  • Curved surface area
  • Volume

\\

Solution:

\\

Using formula:

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA  \: of  \: cylinder = 2\pi rh}}}}}}  \:  \star \\  \\

<em>Substituting the required values: </em>

\\

\dashrightarrow \:  \:  \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times  10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 2 \times 22 \times 10 \\  \\ \\   \dashrightarrow \:  \:  \sf CSA {(cylinder)} = 44 \times 10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 440 \:  {cm}^{2}  \\ \\ \\

Now,

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}=  \pi {r}^{2} h}}}}}}  \:  \star \\  \\ \\

<em>Substituting the required values, </em>

\\

\dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \dfrac{22}{7}  \times  {(7)}^{2}  \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \frac{22}{7}  \times 49  \times 10 \\ \\ \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 1540 {cm}^{3}  \\ \\ \\

Hence,

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm
8 0
2 years ago
Read 2 more answers
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