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Harlamova29_29 [7]
2 years ago
15

Please help me!! Solve for 'a'. b=(4*a)-3 ---------- 4

Mathematics
2 answers:
lilavasa [31]2 years ago
8 0

here u go! i hope this is correct :)

velikii [3]2 years ago
4 0
Use Socratic or Photomath 3
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Which ordered pair is a solution of the equation?<br> 7x-2y=-57x−2y=−5
Yuri [45]

Answer:

what ordered pairs?

Step-by-step explanation:

6 0
3 years ago
4/5x+5=9 solve for x please i have 8 questions left!!!!!!!!!!!
NemiM [27]

Answer:

x= 5

Step-by-step explanation:

You need to get rid of the fraction first and to do that you muliply the whole equation by 5 so that your new equation reads 4x+25=45. Then you subtract 25 from both sides so you have 4x=20. Divide both sides by 4 so x=5.

5 0
3 years ago
For what values of X are the statements below true
Galina-37 [17]

Answer:

See solutions below

Step-by-step explanation:

For what values of X are the statements below true

A. 1x>x+1

x >x+1

x-x>1

0x > 1

x > 1/0

X >∞

B) |1-x|>3

The fucntion can both be positive and negative

For the negative function

-(1-x) > 3

-1+x > 3

x > 3+1

x > 4

For the positive function

1-x > 3

-x > 3 - 1

-x > 2

x < -2

Hence the required solutions are x > 4 and x < -2

c) For the equation

|x-15| < 0

-(x - 15) < 0

-x + 15 < 0

-x < -15

x > 15

Also x-15 < 0

x < 0+15

x < 15

Hence the required solution is x > 15 and x < 15

3 0
3 years ago
Divide 12x 4 y 4 by 3x 2 y. A. 4x 6y 5 B. 4x 2y 3 C. 9x 6 D. 9x 2y 3
andrew-mc [135]

Answer:

\frac{12x^4y^4}{3x^2y}=4x^2y^3

Step-by-step explanation:

Consider an element a\neq 0

We know that \frac{a^m}{a^n}=a^{m-n}

Here, m and n are exponents and a is a base. Exponent refers to the no. of times a term is multiplied by itself. Another word for exponents is powers.

Other Properties of exponents:

a^m\times a^n=a^{m+n}\\a^0=1\\\left ( a^m \right )^n=a^{mn}

Here, we are required to divide 12x^4y^4 by 3x^2y.

Consider \frac{12x^4y^4}{3x^2y}

We will solve \frac{12}{3}\,,\,\frac{x^4}{x^2}\,,\,\frac{y^4}{y} separately.

Here,

\frac{12}{3}=4\\\frac{x^4}{x^2}=x^{4-2}=x^2\\\frac{y^4}{y}=y^3

So, \frac{12x^4y^4}{3x^2y}=4x^2y^3

8 0
3 years ago
What's 6 15/40 Simplified ?
Phoenix [80]
 it would be 6 3/8 because the common factor is 5

3 0
3 years ago
Read 2 more answers
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