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masya89 [10]
3 years ago
9

HELP ASAP!!!!! 25 POINTS + BRAINLIEST!!!!!!!

Mathematics
2 answers:
natka813 [3]3 years ago
7 0

Answer:

5

Step-by-step explanation:

Vinvika [58]3 years ago
4 0

Answer:

5

Step-by-step explanation:

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Opposite angles of an inscribed quadrilateral are supplementary?
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according to cyclic quadrilateral properties the oppoaite angles are supplementry

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Math help !! :o <br> will reward<br> written response questions :3
Hitman42 [59]

In the picture with the triangles Phillip is correct because  the triangle does not give the measurements of the same side so there is no proof of any sides to be the same. With the other picture what I did was I reversed the translation which got the points A (-2,1) B (-5,3) Then I reversed the rotation which got me A(2,-1) and B (5,-3). So line AB endpoints would be located A (2,-1) and B (5,-3).

Hope this helps!

5 0
3 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Sonja [21]

Answer:

Step-by-step explanation:

Given that;

Compressed Soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16

Intermediate Soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26

                            Compressed soil           intermediate soil

Mean                      2.907                              3.286

SD                          0.1414                              0.2377

Here we have,

\bar x_1 =3.286\\ \bar x_2 =2.907\\s_1 =0.2377\\ s_2 =0.1414\\n_1=19\\n_2=20

The pooled Standard deviation

s_p=\sqrt{\frac{(n_1-1)s_1^2(n_2-1)s_2^2}{n_1+n_2-2} } \\\\=0.1943

So standard error for difference in population mean is

s_{\bar x_1 - \bar x_2} = \sqrt{\frac{s_p^2}{n_1}+\frac{s_p^2}{n_2}  } \\\\=0.0623

by inputting the values we get 0.0623

Degree of freedom for t is

df = 19 + 20 - 2 = 37,

so t-critical value is 2.715.

So required confidence interval for

\mu_{1} - \mu_{2} will be

( \bar x_1 - \bar x_2) \pm t_{critical}*s_{\bar x_1 - \bar x_2}

=0.3793 \pm2.715*0.063\\\\=0.3793\pm0.1690

So required confidence interval is (0.2103 , 0.5483).

6 0
3 years ago
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